问题
解答题
先化简,再求值:
|
答案
÷(x-1-x2-2x x2-1
),2x-1 x+1
=
÷x(x-2) (x+1)(x-1)
,x2-1-2x+1 x+1
=
•x(x-2) (x+1)(x-1)
,x+1 x(x-2)
=
,1 x-1
当x=6时,原式=
=1 6-1
.1 5
先化简,再求值:
|
÷(x-1-x2-2x x2-1
),2x-1 x+1
=
÷x(x-2) (x+1)(x-1)
,x2-1-2x+1 x+1
=
•x(x-2) (x+1)(x-1)
,x+1 x(x-2)
=
,1 x-1
当x=6时,原式=
=1 6-1
.1 5