问题
解答题
请先将式子(
|
答案
(
+x+2 x-2
)÷4 x2-4x+4 x (x-2)2
=[
+(x+2)(x-2) (x-2)2
]•4 (x-2)2 (x-2)2 x
=
•x2 (x-2)2 (x-2)2 x
=x,
当x=1时,原式=1.(当x=2,无意义;当x=15时,原式=15.)
请先将式子(
|
(
+x+2 x-2
)÷4 x2-4x+4 x (x-2)2
=[
+(x+2)(x-2) (x-2)2
]•4 (x-2)2 (x-2)2 x
=
•x2 (x-2)2 (x-2)2 x
=x,
当x=1时,原式=1.(当x=2,无意义;当x=15时,原式=15.)