问题
解答题
已知x+y=-4，xy=-12，求
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答案
原式=(y+1)2+(x+1)2 (x+1)(y+1)
=x2+y2+2(x+y)+2 xy+x+y+1
=(x+y)2-2xy+2(x+y)+2 xy+x+y+1
∵x+y=-4，xy=-12，
∴原式=
=-16+24-8+2 -12-4+1
．34 15
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已知x+y=-4，xy=-12，求
|
原式=(y+1)2+(x+1)2 (x+1)(y+1)
=x2+y2+2(x+y)+2 xy+x+y+1
=(x+y)2-2xy+2(x+y)+2 xy+x+y+1
∵x+y=-4，xy=-12，
∴原式=
=-16+24-8+2 -12-4+1
．34 15
