问题
解答题
化简求值:
|
答案
原式=
a |
a(a-2) |
1 |
a-3 |
a-2 |
(a-3)(a+3) |
=
a(a-3)(a+3) |
a(a-2)(a-3)(a+3) |
a(a-2)(a+3) |
a(a-2)(a-3)(a+3) |
a(a-2)2 |
a(a-2)(a-3)(a+3) |
=
a3-5a2+a |
a(a-2)(a-3)(a+3) |
当a=1时,原式=
1-5+1 |
1×(1-2)×(1-3)×(1+3) |
3 |
8 |
化简求值:
|
原式=
a |
a(a-2) |
1 |
a-3 |
a-2 |
(a-3)(a+3) |
=
a(a-3)(a+3) |
a(a-2)(a-3)(a+3) |
a(a-2)(a+3) |
a(a-2)(a-3)(a+3) |
a(a-2)2 |
a(a-2)(a-3)(a+3) |
=
a3-5a2+a |
a(a-2)(a-3)(a+3) |
当a=1时,原式=
1-5+1 |
1×(1-2)×(1-3)×(1+3) |
3 |
8 |