问题
解答题
计算(
|
答案
原式=[
-a+1 a(a-1)
]•4 (a+1)(a-1) (a+1)2 a-1
=
•(a+1)2-4a a(a+1)(a-1) (a+1)2 a-1
=
•(a-1)2 a(a+1)(a-1)
=(a+1)2 a-1
．a+1 a
搜题请搜索小程序“爱下问搜题”
计算(
|
原式=[
-a+1 a(a-1)
]•4 (a+1)(a-1) (a+1)2 a-1
=
•(a+1)2-4a a(a+1)(a-1) (a+1)2 a-1
=
•(a-1)2 a(a+1)(a-1)
=(a+1)2 a-1
．a+1 a