问题
解答题
先化简,再求值:
|
答案
原式=
•x-1 x+2
+x2-4 x2-2x+1 2 x-1
=
•x-1 x+2
+(x+2)(x-2) (x-1)2 2 x-1
=
+x-2 x-1 2 x-1
=x-2+2 x-1
=
.x x-1
当x=2时,原式=
=2.2 2-1
先化简,再求值:
|
原式=
•x-1 x+2
+x2-4 x2-2x+1 2 x-1
=
•x-1 x+2
+(x+2)(x-2) (x-1)2 2 x-1
=
+x-2 x-1 2 x-1
=x-2+2 x-1
=
.x x-1
当x=2时,原式=
=2.2 2-1