问题 解答题
计算:
(1)(-2m2n-22•(3m-1n3-3
(2)(
a
a2-b2
-
1
a+b
b
b-a
答案

(1)原式=4m4n-4

1
27
m3n-9

=

4
27
m7n-13

=

4m7
27n13

(2)原式=[

a-(a-b)
(a+b)(a-b)
-(a-b)
b

=

b
(a+b)(a-b)
-(a-b)
b

=-

1
a+b

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