问题
解答题
计算 (1)(
(2)(2+
|
答案
(1)原式=(
)÷x2+x-2-x2 -2x-1 (x+1)(x+2)
=x+3 (x+2)2
×-(x+3) (x+1)(x+2)
=-(x+2)2 x+3
;x+2 x+1
(2)原式=(2+
+2-3
)(2+3
-2+3
)=83
.3
计算 (1)(
(2)(2+
|
(1)原式=(
)÷x2+x-2-x2 -2x-1 (x+1)(x+2)
=x+3 (x+2)2
×-(x+3) (x+1)(x+2)
=-(x+2)2 x+3
;x+2 x+1
(2)原式=(2+
+2-3
)(2+3
-2+3
)=83
.3