问题
解答题
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答案
原式=
-xy2 (x-y)(x+y)
×x4y (x2+y2)(x2-y2) x2+y2 x2
=
-xy2 (x-y)(x+y)
=x2y (x-y)(x+y)
=xy2-x2y (x-y)(x+y)
=-xy(y-x) (x-y)(x+y)
．xy x+y
故答案为-
．xy x+y
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原式=
-xy2 (x-y)(x+y)
×x4y (x2+y2)(x2-y2) x2+y2 x2
=
-xy2 (x-y)(x+y)
=x2y (x-y)(x+y)
=xy2-x2y (x-y)(x+y)
=-xy(y-x) (x-y)(x+y)
．xy x+y
故答案为-
．xy x+y