问题 解答题
先化简(1+
1
x
x2-1
x2
,再求值(其中x是满足-2<x≤2的整数)
答案

(1+

1
x
x2-1
x2

=

x+1
x
x2
(x+1)(x-1)

=

x
x-1

当x是满足-2<x≤2的整数,x=-1,0,1,2.

而要使原分式有意义,x≠±1,且x≠0,

即x=2,

当x=2时,原式=

2
2-1
=2.

问答题 简答题
问答题