问题
解答题
先化简代数式(
|
答案
原式=[
+a+1 a-1
]•1 (a-1)2 a-1 a
=
•(a+1)(a-1)+1 (a-1)2 a-1 a
=
•a2 (a-1)2 a-1 a
=
,a a-1
∵
=1+a+1 2a
,1 a
而a≠0,
∴a+1=2a+1,
∴a=-1,
当a=-1时,原式=
=-1 -1-1
.1 2
先化简代数式(
|
原式=[
+a+1 a-1
]•1 (a-1)2 a-1 a
=
•(a+1)(a-1)+1 (a-1)2 a-1 a
=
•a2 (a-1)2 a-1 a
=
,a a-1
∵
=1+a+1 2a
,1 a
而a≠0,
∴a+1=2a+1,
∴a=-1,
当a=-1时,原式=
=-1 -1-1
.1 2