问题
解答题
计算: (1)(
(2)[
|
答案
(1)原式=-
ab;4 5
(2)原式=[
-m-n (m-n)2
]•n(m+n) (m+n)(m-n) mn n-1
=
•1-n m-n mn n-1
=-
.mn m-n
计算: (1)(
(2)[
|
(1)原式=-
ab;4 5
(2)原式=[
-m-n (m-n)2
]•n(m+n) (m+n)(m-n) mn n-1
=
•1-n m-n mn n-1
=-
.mn m-n