问题 解答题
计算:
(1)(-1)3+(2012-
2
)0
-(
1
2
)-2

(2)
(a+b)2
ab
-
(a-b)2
ab

(3)
3
x-4
-
24
x2-16

(4)
x2-2x+1
x2-1
÷
x-1
x2+x
答案

(1)原式=-1+1-4

=-4;

(2)原式=

a2+2ab+b2-(a2-2ab+b2)
ab

=

4ab
ab

=4;

(3)原式=

3(x+4)
(x+4)(x-4)
-
24
(x+4)(x-4)

=

3x-12
(x+4)(x-4)

=

3(x-4)
(x+4)(x-4)

=

3
x+4

(4)原式=

(x-1)2
(x+1)(x-1)
x(x+1)
x-1

=x.

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