问题
解答题
计算: (1)
(2)(y-
|
答案
(1)原式=
=x2+y2-2xy x-y
=x-y;(x-y)2 x-y
(2)原式=
÷xy-1 x
=xy-1 y
•xy-1 x
=y xy-1
.y x
计算: (1)
(2)(y-
|
(1)原式=
=x2+y2-2xy x-y
=x-y;(x-y)2 x-y
(2)原式=
÷xy-1 x
=xy-1 y
•xy-1 x
=y xy-1
.y x