问题
解答题
计算: (1)(
(2)(-
|
答案
(1)原式=
•4a2 b2
-1 a-b
•a b 4 b
=
-4a2 b2(a-b) 4a b2
=
-4a2 b2(a-b) 4a(a-b) b2(a-b)
=
;4a2-4a2+4ab b2(a-b)
(2)原式=4-8×0.125+1+1
=4-1+1+1
=5.
计算: (1)(
(2)(-
|
(1)原式=
•4a2 b2
-1 a-b
•a b 4 b
=
-4a2 b2(a-b) 4a b2
=
-4a2 b2(a-b) 4a(a-b) b2(a-b)
=
;4a2-4a2+4ab b2(a-b)
(2)原式=4-8×0.125+1+1
=4-1+1+1
=5.