问题
解答题
已知y=
|
答案
y=
÷x2+2x+1 x2-1
-x+1x+1 x2-x
=
×(x+1)2 (x+1)(x-1)
-x+1x(x-1) x+1
=x-x+1
=1．
所以不论x为何值y的值不变．
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已知y=
|
y=
÷x2+2x+1 x2-1
-x+1x+1 x2-x
=
×(x+1)2 (x+1)(x-1)
-x+1x(x-1) x+1
=x-x+1
=1．
所以不论x为何值y的值不变．