问题
解答题
|
答案
原式=
-1 x+1
×x+3 (x+1)(x-1) (x-1)2 (x+1)(x+3)
=
-1 x+1 x-1 (x+1)2
=
,2 (x+1)2
当x=-3时,原式=
=2 (-3+1)2
.1 2
|
原式=
-1 x+1
×x+3 (x+1)(x-1) (x-1)2 (x+1)(x+3)
=
-1 x+1 x-1 (x+1)2
=
,2 (x+1)2
当x=-3时,原式=
=2 (-3+1)2
.1 2