问题
解答题
计算: (1)(
(2)
|
答案
(1)原式=
•x2-4 x+2 x x-2
=
•(x+2)(x-2) x+2 x x-2
=x;
(2)原式=
•x-1 x+2
+(x+2)(x-2) (x-1)2 1 x-1
=
+x-2 x-1 1 x-1
=x-2+1 x-1
=1.
(2)原式=
•x-1 x+2
+x2-4 x2-2x+1
=1 x-1
•x-1 x+2
+(x+2)(x-2) (x-1)2
=1 x-1
+x-2 x-1
=1 x-1
=x-2+1 x-1
=1.x-1 x-1