问题 解答题
计算:
(1)(
x2
x+2
-
4
x+2
x-2
x

(2)
x-1
x+2
÷
x2-2x+1
x2-4
+
1
x-1
答案

(1)原式=

x2-4
x+2
x
x-2

=

(x+2)(x-2)
x+2
x
x-2

=x;

(2)原式=

x-1
x+2
(x+2)(x-2)
(x-1)2
+
1
x-1

=

x-2
x-1
+
1
x-1

=

x-2+1
x-1

=1.

(2)原式=

x-1
x+2
x2-4
x2-2x+1
+
1
x-1
=
x-1
x+2
(x+2)(x-2)
(x-1)2
+
1
x-1
=
x-2
x-1
+
1
x-1
=
x-2+1
x-1
=
x-1
x-1
=1.

单项选择题 A1/A2型题
单项选择题