问题
解答题
计算：（1）
|
答案
（1）原式=
| (x-3)2 |
| x |
| x2 |
| (x+3)(x-3) |
| x(x-3) |
| x+3 |
（2）原式=
| 1 |
| m+2 |
| 4 |
| (m+2)(m-2) |
=
| m-2+4 |
| (m+2)(m-2) |
=
| m+2 |
| (m+2)(m-2) |
=
| 1 |
| m-2 |
故答案为
| x(x-3) |
| x+3 |
| 1 |
| m-2 |
搜题请搜索小程序“爱下问搜题”
计算：（1）
|
（1）原式=
| (x-3)2 |
| x |
| x2 |
| (x+3)(x-3) |
| x(x-3) |
| x+3 |
（2）原式=
| 1 |
| m+2 |
| 4 |
| (m+2)(m-2) |
=
| m-2+4 |
| (m+2)(m-2) |
=
| m+2 |
| (m+2)(m-2) |
=
| 1 |
| m-2 |
故答案为
| x(x-3) |
| x+3 |
| 1 |
| m-2 |