问题
解答题
|
答案
-1 a+1
×a+3 a2-1 a2-2a+1 (a+1)(a+3)
=
-1 a+1
×a+3 (a+1)(a-1) (a-1)2 (a+1)(a+3)
=
-1 a+1
=a-1 (a+1)2
=a+1-a+1 (a+1)2
=2 (a+1)2
;2 a2+2a+1
当a2+2a-1=0即a2+2a=1时,原式=
=1.2 1+1
|
-1 a+1
×a+3 a2-1 a2-2a+1 (a+1)(a+3)
=
-1 a+1
×a+3 (a+1)(a-1) (a-1)2 (a+1)(a+3)
=
-1 a+1
=a-1 (a+1)2
=a+1-a+1 (a+1)2
=2 (a+1)2
;2 a2+2a+1
当a2+2a-1=0即a2+2a=1时,原式=
=1.2 1+1