问题
解答题
(
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答案
原式=[
-x+2 x(2x-3)
]÷x(x+2) (x+2)(2x-3) 2x-3-1 2(2x-3)
=
•x+2-x2 x(2x-3) 2x-3 x-2
=-(x+1)(x-2) x(x-2)
=-
.x+1 x
(
|
原式=[
-x+2 x(2x-3)
]÷x(x+2) (x+2)(2x-3) 2x-3-1 2(2x-3)
=
•x+2-x2 x(2x-3) 2x-3 x-2
=-(x+1)(x-2) x(x-2)
=-
.x+1 x