问题 填空题
计算:
a2
a+b
-a-b=______,(
1
x2
-
1
a2
)÷(
1
x
+
1
a
)
=______.
答案

a2
a+b
-a-b

=

a2-(a+b)2
a+b

=-

2ab+b2
a+b

(

1
x2
-
1
a2
)÷(
1
x
+
1
a
)

=

(
1
x
+
1
a
)(
1
x
-
1
a
)
1
x
+
1
a

=

1
x
-
1
a

=

a-x
ax

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