问题
问答题
将250mLH2SO4的质量分数为98%,密度为1.84g/cm3的浓硫酸稀释到1000mL.
(1)此时溶液中H2SO4的物质的量是多少?
(2)此时溶液中H+的物质的量浓度是多少?
答案
(1)m(H2SO4)=250ml×1.84g/ml×98%=450.8g,
n(H2SO4)=
=4.6mol,450.8g 98g/mol
答:此时溶液中H2SO4的物质的量是4.6mol.
(2)250mLH2SO4的质量分数为98%的c(H2SO4)=
=1000ρw M
=18.4mol/L,1000×1.84g/L×98% 98g/mol
稀释后:c(H2SO4)=
=4.6mol/L,18.4mol/L×0.25L 1L
c(H+)=2c(H2SO4)=2×4.6mol/L=9.2mol/L,
答:此时溶液中H+的物质的量浓度是9.2mol/L.