问题 问答题

将250mLH2SO4的质量分数为98%,密度为1.84g/cm3的浓硫酸稀释到1000mL.

(1)此时溶液中H2SO4的物质的量是多少?

(2)此时溶液中H+的物质的量浓度是多少?

答案

(1)m(H2SO4)=250ml×1.84g/ml×98%=450.8g,

n(H2SO4)=

450.8g
98g/mol
=4.6mol,

答:此时溶液中H2SO4的物质的量是4.6mol.

(2)250mLH2SO4的质量分数为98%的c(H2SO4)=

1000ρw
M
=
1000×1.84g/L×98%
98g/mol
=18.4mol/L,

稀释后:c(H2SO4)=

18.4mol/L×0.25L
1L
=4.6mol/L,

c(H+)=2c(H2SO4)=2×4.6mol/L=9.2mol/L,

答:此时溶液中H+的物质的量浓度是9.2mol/L.

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