问题
解答题
| 化简求值： (1)
(2)(
|
答案
（1）原式=
| (2a-b)2 |
| 2a-b |
| 1 |
| (2a+b)(2a-b) |
| 1 |
| 2a+b |
把a=
| 1 |
| 2 |
| 1 |
| 4 |
（2）原式=[
| x+2 |
| x(x-2) |
| x-1 |
| (x-2)2 |
| x |
| x-4 |
| x-4 |
| x(x-2)2 |
| x |
| x-4 |
| 1 |
| (x-2)2 |
把x=3代入得，原式=1．
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| 化简求值： (1)
(2)(
|
（1）原式=
| (2a-b)2 |
| 2a-b |
| 1 |
| (2a+b)(2a-b) |
| 1 |
| 2a+b |
把a=
| 1 |
| 2 |
| 1 |
| 4 |
（2）原式=[
| x+2 |
| x(x-2) |
| x-1 |
| (x-2)2 |
| x |
| x-4 |
| x-4 |
| x(x-2)2 |
| x |
| x-4 |
| 1 |
| (x-2)2 |
把x=3代入得，原式=1．