问题
解答题
先化简,再求值:
|
答案
原式=
÷((x-2)(x+2) x(x+2)
-x2+4 x
)4x x
=
÷(x-2)(x+2) x(x+2) x2-4x+4 x
=
÷(x-2)(x+2) x(x+2) (x-2)2 x
=
•(x-2)(x+2) x(x+2) x (x-2)2
=
,1 x-2
当x=
时,原式=5
=1
-25
+2.5
先化简,再求值:
|
原式=
÷((x-2)(x+2) x(x+2)
-x2+4 x
)4x x
=
÷(x-2)(x+2) x(x+2) x2-4x+4 x
=
÷(x-2)(x+2) x(x+2) (x-2)2 x
=
•(x-2)(x+2) x(x+2) x (x-2)2
=
,1 x-2
当x=
时,原式=5
=1
-25
+2.5