问题 解答题
计算或化简
(1)计算:(-1)2013-(
3
-
2
)0+(
1
2
)-1

(2)化简:(
x2
x+4
-
16
x+4
x-4
x

(3)化简:(1-
1
a-1
a2-4a+4
a2-a

(4)先化简(
a
a+2
+
2
a-2
1
a2-4
,然后选取一个合适的整数a代入求值,其中-2≤a≤2.
答案

(1)原式=-1-1+2

=0;

(2)原式=

(x+4)(x-4)
x+4
÷
x-4
x

=(x-4)×

x
x-4

=x;

(3)原式=

a-2
a-1
÷
(a-2)2
a(a-1)

=

a-2
a-1
×
a(a-1)
(a-2)2

=

a
a-2

(4)原式=

a(a-2)+2(a+2)
(a+2)(a-2)
×(a+2)(a-2)

=a(a-2)+2(a+2)

=a2-2a+2a+4

=a2+4,

当a=1时,原式=1+4=5.

单项选择题
单项选择题 A1型题