问题
解答题
先化简,再求值: (1)(x-2)(x+1)-x(x-3),其中x=3. (2)先化简:(
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答案
(1)原式=x2-x-2-x2+3x
=2x-2,
当x=3时,原式=2×3-2=4;
(2)原式=
÷3-x2+1 x+1 (x-2)2 x+1
=
•-(x+2)(x-2) x+1 x+1 (x-2)2
=
,-x-2 x-2
当x=1时,原式=
=3.-1-2 1-2
先化简,再求值: (1)(x-2)(x+1)-x(x-3),其中x=3. (2)先化简:(
|
(1)原式=x2-x-2-x2+3x
=2x-2,
当x=3时,原式=2×3-2=4;
(2)原式=
÷3-x2+1 x+1 (x-2)2 x+1
=
•-(x+2)(x-2) x+1 x+1 (x-2)2
=
,-x-2 x-2
当x=1时,原式=
=3.-1-2 1-2