问题
解答题
先化简,再求值:(
|
答案
(
-a-1 a2-4a+4
)÷(a+2 a2-2a
-1)4 a
=
•a(a-1)-(a+2)(a-2) a(a-2)2 a 4-a
=
•4-a a(a-2)2 a 4-a
=
,1 (a-2)2
∵解不等式组得
<a<5,3 2
∴a=2,3,4,
∵原式中a≠0,2,4,
∴a=3,
∴当a=3时,原式=
=1.1 (3-2)2
先化简,再求值:(
|
(
-a-1 a2-4a+4
)÷(a+2 a2-2a
-1)4 a
=
•a(a-1)-(a+2)(a-2) a(a-2)2 a 4-a
=
•4-a a(a-2)2 a 4-a
=
,1 (a-2)2
∵解不等式组得
<a<5,3 2
∴a=2,3,4,
∵原式中a≠0,2,4,
∴a=3,
∴当a=3时,原式=
=1.1 (3-2)2