问题 解答题
先化简,再求值:(
3x+2
x2-1
)+
x
x+1
,其中x=(-1)2012+tan60°.
答案

原式=

3x+2
(x+1)(x-1)
+
x(x-1)
(x+1)(x-1)

=

3x+2+x2-x
(x+1)(x-1)

=

2x+2+x2
(x+1)(x-1)

=

(x+1)2+1
(x+1)(x-1)

∵x=(-1)2012+tan60°=1+

3

∴原式=

(1+
3
+1)2+1
(1+
3
+1)(1+
3
-1)

=

(2+
3
)
2
+1
(2+
3
3

=

4+3+4
3
+1
2
3
+3

=

4(2+
3
)
2
3
+3

=

4
3
3

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