问题
解答题
先化简,再求值:(
|
答案
原式=[
+1 x+1
]•(x-1)2 (x+1)(x-1) x+1 x-1
=
•x x+1 x+1 x-1
=
,x x-1
当x=
-1时,原式=2
=-
-12
-1-12
.2 2
先化简,再求值:(
|
原式=[
+1 x+1
]•(x-1)2 (x+1)(x-1) x+1 x-1
=
•x x+1 x+1 x-1
=
,x x-1
当x=
-1时,原式=2
=-
-12
-1-12
.2 2