问题 解答题
(1)计算:(-1)2012-|1-6tan30°|-(-
5
)0+
12

(2)解方程组:
2x-y=-5…①
3x+2y=-4…②

(3)先化简,再求值:
x-y
x+3y
÷
x2-y2
x2+6xy+9y2
-
3y
x+y
,其中x=-
1
2
,y=-1.
答案

(1)(-1)2012-|1-6tan30°|-(-

5
)0+
12

=1-(2

3
-1)-1+2
3

=1;

(2)

2x-y=-5…①
3x+2y=-4…②

由①×2得:4x-2y=-10,③,

③+②得:7x=-14,

x=-2,

把x=-2代入①得:y=1,

所以方程组的解是

x=-2
y=1

(3)

x-y
x+3y
÷
x2-y2
x2+6xy+9y2
-
3y
x+y

=

x-y
x+3y
×
(x+3y)2
(x+y)(x-y)
-
3y
x+y

=

x+3y
x+y
-
3y
x+y

=

x
x+y

x=-

1
2
,y=-1代入上式得:
-
1
2
-
1
2
-1
=
1
3

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