问题
解答题
(1)计算:(-1)2012-|1-6tan30°|-(-
(2)解方程组:
(3)先化简,再求值:
|
答案
(1)(-1)2012-|1-6tan30°|-(-
)0+5 12
=1-(2
-1)-1+23 3
=1;
(2)
,2x-y=-5…① 3x+2y=-4…②
由①×2得:4x-2y=-10,③,
③+②得:7x=-14,
x=-2,
把x=-2代入①得:y=1,
所以方程组的解是
.x=-2 y=1
(3)
÷x-y x+3y
-x2-y2 x2+6xy+9y2 3y x+y
=
×x-y x+3y
-(x+3y)2 (x+y)(x-y) 3y x+y
=
-x+3y x+y 3y x+y
=
,x x+y
把x=-
,y=-1代入上式得:1 2
=- 1 2 -
-11 2
.1 3