先化简,再求值: (1)
(2)
|
(1)原式=
-2a (a+2)(a-2) a+2 (a+2)(a-2)
=2a-a-2 (a+2)(a-2)
=a-2 (a+2)(a-2)
=
,1 a+2
当a=
时,原式=1 2
=1
+21 2
;2 5
(2)原式=
+(a+2b)(a-b) (a+b)(a-b)
-2b2 (a+b)(a-b) 2ab (a+b)(a-b)
=a2+ab-2b2+2b2-2ab (a+b)(a-b)
=a2-ab (a+b)(a-b)
=a(a-b) (a+b)(a-b)
=
,a a+b
当a=-2,b=
时,原式=1 3
=-2 -2+ 1 3
.6 5