问题
计算题
先化简,再求值.已知a=﹣2,b=5,A=a2+2ab+b2,B=a2﹣2ab+b2;求3A﹣(B+2A)的值.
答案
解:3A﹣(B+2A)
=3A﹣B﹣2A
=A﹣B,
当A=a2+2ab+b2,B=a2﹣2ab+b2,a=﹣2,b=5时,
A﹣B=a2+2ab+b2﹣(a2﹣2ab+b2)
=a2+2ab+b2﹣a2+2ab﹣b2
=4ab
=4×(﹣2)×5
=﹣40.
先化简,再求值.已知a=﹣2,b=5,A=a2+2ab+b2,B=a2﹣2ab+b2;求3A﹣(B+2A)的值.
解:3A﹣(B+2A)
=3A﹣B﹣2A
=A﹣B,
当A=a2+2ab+b2,B=a2﹣2ab+b2,a=﹣2,b=5时,
A﹣B=a2+2ab+b2﹣(a2﹣2ab+b2)
=a2+2ab+b2﹣a2+2ab﹣b2
=4ab
=4×(﹣2)×5
=﹣40.