问题
计算题
先化简,再求值:x2﹣(5x2﹣4y)+3(x2﹣y),其中x=﹣1,y=2.
答案
解:x2﹣(5x2﹣4y)+3(x2﹣y)
=x2﹣5x2+4y+3x2﹣3y
=﹣x2+y;
∴当x=﹣1,y=2时,原式=﹣(﹣1)2+2=1.
先化简,再求值:x2﹣(5x2﹣4y)+3(x2﹣y),其中x=﹣1,y=2.
解:x2﹣(5x2﹣4y)+3(x2﹣y)
=x2﹣5x2+4y+3x2﹣3y
=﹣x2+y;
∴当x=﹣1,y=2时,原式=﹣(﹣1)2+2=1.