问题
实验题
“测量小灯泡的电功率”实验的目的是测定小灯泡的额定功率和不在额定电压下工作的功率.所依据的原理是P=IU. 因此，本实验需要测量的物理量是：
(1)加在小灯泡两端的 .
(2)通过小灯泡的 .
(3)测量它们的仪器是 和 .
(4)为了调节小灯泡两端电压应选择 与小灯泡串联.
答案
（1）电压
（2）电流
（3）电压表；电流表
（4）滑动变阻器
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“测量小灯泡的电功率”实验的目的是测定小灯泡的额定功率和不在额定电压下工作的功率.所依据的原理是P=IU. 因此，本实验需要测量的物理量是：
(1)加在小灯泡两端的 .
(2)通过小灯泡的 .
(3)测量它们的仪器是 和 .
(4)为了调节小灯泡两端电压应选择 与小灯泡串联.
（1）电压
（2）电流
（3）电压表；电流表
（4）滑动变阻器
小题3: their sons were at school. The 小题4: seemed hopeless. Two weeks later, however, Mr. Chen got some good news. A health care project would 小题5: medical treatment for poor patients in western China. They 小题6: to pay only half the cost or even less. Thanks to the project, he was able to receive an operation just in time to prevent(防止) the illness from getting 小题7: . Now he has returned to his family. The 小题8: of this health care project is to improve the situation of poor people in western China. So far, the project 小题9: more than 5,000 people. The Chinese government 小题10: to develop a new health care model for China. As our country develops, we must remember to care for the weakest members. |