问题
解答题
化简:
(1)(4x2y-3xy2)-(1+4x2y-3xy2)
(2)4y2-[3y-(3-2y)-2y2]
答案
(1)去括号得:原式=4x2y-3xy2-1-4x2y+3xy2;合并同类项得:原式=-1;
(2)去括号得:原式=4y2-3y+3-2y+2y2;合并同类项得:原式=6y2-5y+3;
化简:
(1)(4x2y-3xy2)-(1+4x2y-3xy2)
(2)4y2-[3y-(3-2y)-2y2]
(1)去括号得:原式=4x2y-3xy2-1-4x2y+3xy2;合并同类项得:原式=-1;
(2)去括号得:原式=4y2-3y+3-2y+2y2;合并同类项得:原式=6y2-5y+3;