问题
填空题
用换元法解方程x2-3x+
|
答案
x2-3x+
=5,8 x2-3x+1
设x2-3x+1=y,则原方程化为y-1+
=5,8 y
y2-y+8=5y
y2-y-5y+8=0,
y2-6y+8=0,
故答案为:y2-6y+8=0.
用换元法解方程x2-3x+
|
x2-3x+
=5,8 x2-3x+1
设x2-3x+1=y,则原方程化为y-1+
=5,8 y
y2-y+8=5y
y2-y-5y+8=0,
y2-6y+8=0,
故答案为:y2-6y+8=0.