问题 解答题
合并同类项
(1)3a2+2a-2-a2-5a+7
(2)2(x2y+xy)-4(2x2y2-
1
2
y2x2)-(5xy+6x2y)
答案

(1)原式=2a2-3a+5;

(2)原式=2x2y+2xy-8x2y2+2x2y2-5xy-6x2y=-6x2y2-4x2y-3xy.

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