问题
解答题
合并同类项 (1)3a2+2a-2-a2-5a+7 (2)2(x2y+xy)-4(2x2y2-
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答案
(1)原式=2a2-3a+5;
(2)原式=2x2y+2xy-8x2y2+2x2y2-5xy-6x2y=-6x2y2-4x2y-3xy.
合并同类项 (1)3a2+2a-2-a2-5a+7 (2)2(x2y+xy)-4(2x2y2-
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(1)原式=2a2-3a+5;
(2)原式=2x2y+2xy-8x2y2+2x2y2-5xy-6x2y=-6x2y2-4x2y-3xy.