问题
解答题
先化简,再求值: 2x2+(-x2-2xy+2y2)-3(x2-xy+2y2),其中x=2,y=-
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答案
2x2+(-x2-2xy+2y2)-3(x2-xy+2y2)
=-2x2+xy-4y2
当x=2,y=-
时,原式=-10.1 2
先化简,再求值: 2x2+(-x2-2xy+2y2)-3(x2-xy+2y2),其中x=2,y=-
|
2x2+(-x2-2xy+2y2)-3(x2-xy+2y2)
=-2x2+xy-4y2
当x=2,y=-
时,原式=-10.1 2