若x4+y4=25,x2y-xy2=6,求x4-y4-x2y+3xy2-2x2y+2y4的值.
x4-y4-x2y+3xy2-2x2y+2y4
=x4+y4-3x2y+3xy2
=(x4+y4)-3(x2y-xy2),
当x4+y4=25,x2y-xy2=6时,原式=25-3×6=7.
若x4+y4=25,x2y-xy2=6,求x4-y4-x2y+3xy2-2x2y+2y4的值.
x4-y4-x2y+3xy2-2x2y+2y4
=x4+y4-3x2y+3xy2
=(x4+y4)-3(x2y-xy2),
当x4+y4=25,x2y-xy2=6时,原式=25-3×6=7.