问题
解答题
先化简,再求值: (1)x2+2x+3(x2-
(2)(5x2-3y2)-3(x2-y2)-(-y2),其中x=5,y=-3. |
答案
(1)原式=x2+2x+3x2-2x
=4x2
将x=-
代入得:原式=4×(-1 2
)2=1;1 2
(2)(5x2-3y2)-3(x2-y2)-(-y2)
=5x2-3y2-3x2+3y2+y2
=2x2+y2
当x=5,y=-3时,
原式=2×52+(-3)2
=59.