问题
解答题
已知x2+y2=7,xy=1,求代数式5x2-(3xy+4y2)-(11xy-2y2)-7x2的值.
答案
∵x2+y2=7,xy=1,
∴5x2-(3xy+4y2)-(11xy-2y2)-7x2
=5x2-3xy-4y2-11xy+2y2-7x2
=-2x2-14xy-2y2
=-2(x2+y2)-14xy
=-14-14
=-28.
已知x2+y2=7,xy=1,求代数式5x2-(3xy+4y2)-(11xy-2y2)-7x2的值.
∵x2+y2=7,xy=1,
∴5x2-(3xy+4y2)-(11xy-2y2)-7x2
=5x2-3xy-4y2-11xy+2y2-7x2
=-2x2-14xy-2y2
=-2(x2+y2)-14xy
=-14-14
=-28.