问题 解答题

已知x2+y2=7,xy=1,求代数式5x2-(3xy+4y2)-(11xy-2y2)-7x2的值.

答案

∵x2+y2=7,xy=1,

∴5x2-(3xy+4y2)-(11xy-2y2)-7x2

=5x2-3xy-4y2-11xy+2y2-7x2

=-2x2-14xy-2y2

=-2(x2+y2)-14xy

=-14-14

=-28.

单项选择题
单项选择题