问题
解答题
先化简,再求值:-8xy2+3xy-2(xy2-xy),其中x=
|
答案
-8xy2+3xy-2(xy2-xy)
=-8xy2+3xy-2xy2+2xy
=-10xy2+5xy.
当x=
,y=-2时,1 5
原式=-10xy2+5xy
=-10×
×(-2)2+5×1 5
×(-2)1 5
=-8-2
=-10.
先化简,再求值:-8xy2+3xy-2(xy2-xy),其中x=
|
-8xy2+3xy-2(xy2-xy)
=-8xy2+3xy-2xy2+2xy
=-10xy2+5xy.
当x=
,y=-2时,1 5
原式=-10xy2+5xy
=-10×
×(-2)2+5×1 5
×(-2)1 5
=-8-2
=-10.