问题
解答题
先化简再求值:3x2y-[2xy2-2(xy-
|
答案
原式=3x2y-[2xy2-(2xy-3x2y)+xy]+3xy2
=3x2y-(2xy2-2xy+3x2y+xy)+3xy2
=3x2y-2xy2+2xy-3x2y-xy+3xy2
=xy+xy2,
当x=
,y=-5时,1 3
原式=
×(-5)+1 3
×25=1 3
.20 3
先化简再求值:3x2y-[2xy2-2(xy-
|
原式=3x2y-[2xy2-(2xy-3x2y)+xy]+3xy2
=3x2y-(2xy2-2xy+3x2y+xy)+3xy2
=3x2y-2xy2+2xy-3x2y-xy+3xy2
=xy+xy2,
当x=
,y=-5时,1 3
原式=
×(-5)+1 3
×25=1 3
.20 3