问题
解答题
先化简,再求值. 2(2xy2-
|
答案
原式=4xy2-y2-4xy2-
y2+x2y-2 3
y2=-3y2+x2y.4 3
当x=
,y=-3 2
时,原式=-3×(-1 3
)2+(1 3
)2×(-3 2
)1 3
=-
-1 3 3 4
=-
.13 12
先化简,再求值. 2(2xy2-
|
原式=4xy2-y2-4xy2-
y2+x2y-2 3
y2=-3y2+x2y.4 3
当x=
,y=-3 2
时,原式=-3×(-1 3
)2+(1 3
)2×(-3 2
)1 3
=-
-1 3 3 4
=-
.13 12