问题
解答题
2[
|
答案
原式=2[
x-4 3
x+2 3
]-1 2
x3 4
=2[
x+2 3
]-1 2
x3 4
=
x+1-4 3
x3 4
=
x-16 12
x+19 12
=
x+1.7 12
2[
|
原式=2[
x-4 3
x+2 3
]-1 2
x3 4
=2[
x+2 3
]-1 2
x3 4
=
x+1-4 3
x3 4
=
x-16 12
x+19 12
=
x+1.7 12