问题
解答题
计算 (1)2a+4b2-2ab-3a-4ab+b2 (2)2(2x-y)-2(3x-
|
答案
(1)原式=(4+1)b2+(2-3)a+(-2-4)ab
=5b2-a-6ab;
(2)原式=4x-2y-6x+y
=-2x-y.
计算 (1)2a+4b2-2ab-3a-4ab+b2 (2)2(2x-y)-2(3x-
|
(1)原式=(4+1)b2+(2-3)a+(-2-4)ab
=5b2-a-6ab;
(2)原式=4x-2y-6x+y
=-2x-y.