问题
解答题
已知A=2a2-a,B=a2-2a+1. (1)化简:A-2(A-B)-3; (2)当a=-
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答案
(1)∵A=2a2-a,B=a2-2a+1,
∴A-2(A-B)-3=-A+2B-3
=-2a2+a-2(a2-2a+1)-3
=-3a-1,
(2)∵A=2a2-a,B=a2-2a+1,
∴当a=-
时,1 2
原式=-A+2B+3
=-3a-1+6
=-3×(-
)+51 3
=6.
已知A=2a2-a,B=a2-2a+1. (1)化简:A-2(A-B)-3; (2)当a=-
|
(1)∵A=2a2-a,B=a2-2a+1,
∴A-2(A-B)-3=-A+2B-3
=-2a2+a-2(a2-2a+1)-3
=-3a-1,
(2)∵A=2a2-a,B=a2-2a+1,
∴当a=-
时,1 2
原式=-A+2B+3
=-3a-1+6
=-3×(-
)+51 3
=6.