问题 解答题
先化简再求值:3x-[x-y-(y2-x2)-2y2]-(-2x2+y2+y),其中x=-1,y=-
1
2
答案

原式=3x-[x-y-y2+x2-2y2]+2x2-y2-y

=3x-x+y+y2-x2+2y2+2x2-y2-y

=3x+x2+2y2-y

当x=-1,y=-

1
2
时,原式=-3+1+2×(-
1
2
2+
1
2

=-3+1+2×

1
4
+
1
2

=-3+1+

1
2
+
1
2

=-3+1+1

=-1

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