问题
解答题
先化简再求值:3x-[x-y-(y2-x2)-2y2]-(-2x2+y2+y),其中x=-1,y=-
|
答案
原式=3x-[x-y-y2+x2-2y2]+2x2-y2-y
=3x-x+y+y2-x2+2y2+2x2-y2-y
=3x+x2+2y2-y
当x=-1,y=-
时,原式=-3+1+2×(-1 2
)2+1 2 1 2
=-3+1+2×
+1 4 1 2
=-3+1+
+1 2 1 2
=-3+1+1
=-1