问题 解答题
化简:
(1)3a2b-4ab2-4+5a2b+2ab2+7;
(2)化简求值4x2y-[6xy-2(4xy-2)-x2y]+1,其中x=-
1
2
,y=4.
答案

(1)原式=(3a2b+5a2b)+(2ab2-4ab2)+7-4,

=8a2b-22ab2+3.

(2)原式=4x2y-[6xy-8xy+4-x2y]+1,

=4x2y-6xy+8xy-4+x2y+1,

=5x2y+2xy-3,

当x=-

1
2
,y=4时,原式=5×(
1
2
)
2
×4-2×(-
1
2
)×4=9.

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